alert 코드를 수정하여 자바스크립트 off 상태에서 post 다시 값을 넘겨줄 수 있도록 수정

This commit is contained in:
chicpro
2013-02-01 14:17:43 +09:00
parent 1f773795b8
commit c48b3f4ddc
4 changed files with 41 additions and 18 deletions

View File

@ -1,8 +1,14 @@
<?
global $lo_location;
global $lo_url;
$g4['title'] = "오류가 있습니다.";
include_once('./_common.php');
if($error) {
$g4['title'] = "오류가 있습니다.";
} else {
$g4['title'] = "내용을 확인해 주세요.";
}
include_once(G4_PATH.'/head.sub.php');
// 필수 입력입니다.
// 양쪽 공백 없애기
@ -32,9 +38,6 @@ if($error) {
$header2 = "다음 내용을 확인해 주세요.";
}
?>
<div id="validation_check">
<h1><?=$header2?></h1>
<script>
alert("<? echo $msg; ?>");
@ -42,12 +45,32 @@ document.location.href = "<? echo $url; ?>";
</script>
<noscript>
<div id="validation_check">
<h1><?=$header2?></h1>
<p class="cbg">
<?=$msg2?>
</p>
<? if($post) { ?>
<form method="post" action="<?=$url?>">
<?
foreach($_POST as $key => $value) {
if(strlen($value) < 1)
continue;
if(preg_match("/pass|pwd|capt|url/", $key))
continue;
?>
<input type="hidden" name="<?=$key?>" value="<?=$value?>">
<?
}
?>
<input type="submit" value="돌아가기">
</form>
<? } else { ?>
<div class="btn_confirm">
<a href="<?=$url?>">돌아가기</a>
</div>
<? } ?>
<? /*
<article id="validation_check">
@ -70,10 +93,8 @@ document.location.href = "<? echo $url; ?>";
<a href="<?=$url?>">돌아가기</a>
</article>
*/ ?>
</noscript>
</div>
</noscript>
<?
include_once(G4_PATH.'/tail.sub.php');